My brain hurts. (As the thread title promised it would. I never listen.)![]()
My brain hurts. (As the thread title promised it would. I never listen.)![]()
Look at them yo-yos
That's the way ya TEFL
You play the hang-man in a sweet EP
No, that ain't workin'
That's the way ya TEFL
Get your Thai baht for nothin' and your giks for free...
Is it okay to quote myself?Originally Posted by Plan B
I've got the answer...
After two weighings you are left with 3 balls. You then weigh one against one. If they weigh the same then the discounted ball is the odd one out.
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can i ask.... what will you learn if you weigh six balls against six balls?
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ok i'll tell you... nothing. so that would be a very silly move. think it through
Last edited by LoveBucket; 12th October 2007 at 02:06. Reason: Automerged Doublepost
One side of the scales would tip more than the other because it has a heavier ball. Therefore you could discount 6 balls.Originally Posted by LoveBucket
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or ... maybe the other side could be lighter ?c'mon plan b. i know you're not that dim
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^He he he
That's cunning.
Principle still remains the same though? Looking for a lighter ball, not a heavier ball.
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so.. we don't weigh 6 against 6, right?
Why wouldn't 6 against 6 work?
Alternatively you could weigh 3 against 3 X2 or 4 against 4 (which would workout easier) but it's just different ways of getting the same answer.
Edit: Are we assuming that we don't know if the odd ball is heavier or lighter?
Last edited by Plan B; 12th October 2007 at 03:19.
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yes. we don't know
ok i'll tell you your first move. 1,2,3,4 are A and 5,6,7 and 8 are B
weigh A against B. what happens? i can think of 3 possibilities
I got it.
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Last edited by Plan B; 14th October 2007 at 16:59.
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shhh. (i put it on another thread, so see if they get it) ..well done btw
shame on himOriginally Posted by Plan B
Edited post ^^.
^ Yeah but I prolly never would have got it without the extra clue! Before that best I could do was work it out to work 2/3 of the time.
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nice edit mr B. apparently i have greened you too much recently
No.Originally Posted by re_fuse
How High is a Chinaman.
Ridicule is the burden of genius.
If this doesn't make your brain hurt, I don't know what will!![]()
"Fibonacci Sequences and the Multiperiodicity of the Variable Star UW Herculis"
http://www.chjaa.org/2003/2003_3_3p235.pdf
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